Future School mathematics Close
please wait loading
Introduction

Theorem - Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points. - Mathematics

Assignment sheets pre-test tutorial exam

topic: Circle Geometry-non-collinear

title: Theorem - Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points.

objective: On completion of the lesson the student will be able to prove that ' Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points', and use this knowled

getting started:

Assess your current knowledge of the chosen topic!
Consolidate your current knowledge of the chosen topic with a Teacher presented tutorial.
Test your retention of the mathematics material with the exam.
ASSIGNMENT SHEETS
Print out and complete the assignment sheet to further your knowledge on the material, it's easy.
exit
Array ( [LESSONID] => 10529 [0] => 10529 [TITLE] => Theorem - Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points. [1] => Theorem - Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points. [TOPICID] => 3079 [2] => 3079 [SCOID] => 0010000452 [3] => 0010000452 [OBJECTIVE] => On completion of the lesson the student will be able to prove that ' Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points', and use this knowled [4] => On completion of the lesson the student will be able to prove that ' Any three non-collinear points lie on a unique circle whose centre is the point of concurrency of the perpendicular bisectors of the intervals joining these points', and use this knowled [LESSONCODE] => ML5V4W06 [5] => ML5V4W06 [ATTAINMENTLEVEL] => 8 [6] => 8 [LESSONTYPE] => 0 [7] => 0 [DATAFORMAT] => [8] => [APPTYPE] => FSMaths [9] => FSMaths [APPFOLDERNAME] => FSMaths [10] => FSMaths [TOPIC] => Circle Geometry-non-collinear [11] => Circle Geometry-non-collinear [SUBJECTID] => 2 [12] => 2 [INTROURL] => installedpkg/Intro_ML5V4W06.xml [13] => installedpkg/Intro_ML5V4W06.xml [EXAMURL] => installedpkg/ML5V4W06_lesson.xml [14] => installedpkg/ML5V4W06_lesson.xml )